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4x^2-82x=264
We move all terms to the left:
4x^2-82x-(264)=0
a = 4; b = -82; c = -264;
Δ = b2-4ac
Δ = -822-4·4·(-264)
Δ = 10948
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10948}=\sqrt{4*2737}=\sqrt{4}*\sqrt{2737}=2\sqrt{2737}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-82)-2\sqrt{2737}}{2*4}=\frac{82-2\sqrt{2737}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-82)+2\sqrt{2737}}{2*4}=\frac{82+2\sqrt{2737}}{8} $
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